Answer
$=\dfrac {124}{99}$
Work Step by Step
$1.\overline {25}=1.2525\ldots =1+\dfrac {25}{100}+\dfrac {25}{100^{2}}+\dfrac {25}{1003}+\ldots =1+\dfrac {a_{1}}{1-r}=1+\dfrac {\dfrac {25}{100}}{1-\dfrac {1}{100}}=1+\dfrac {25}{99}=\dfrac {124}{99}$
