Answer
$\Sigma_{k=4}^{12}2^k =8176$
Work Step by Step
$\Sigma_{k=4}^{12}2^k $
$a=2^4=16$
$r=2$
# of terms $= 12-4+1=9$
$$\Sigma_{k=4}^{12}2^k =\frac{16(1-(2)^9)}{1-2}=8176$$
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