Answer
$=\dfrac {\pi }{\pi -1}$
Work Step by Step
$1+\dfrac {1}{\pi }+\dfrac {1}{\pi ^{2}}+\dfrac {1}{\pi ^{3}}...=\dfrac {a_{1}}{1-r}=\dfrac {1}{1-\dfrac {1}{\pi }}=\dfrac {\pi }{\pi -1}$
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