Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises: 47

Answer

$=\dfrac {37}{999}$

Work Step by Step

$0.\overline {037}=0.037037...=\dfrac {37}{1000}+\dfrac {37}{\left( 1000\right) ^{2}}+\ldots \dfrac {a_{1}}{1-r}=\dfrac {\dfrac {32}{1000}}{1-\dfrac {1}{1000}}=\dfrac {37}{999}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.