Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises - Page 623: 47


$=\dfrac {37}{999}$

Work Step by Step

$0.\overline {037}=0.037037...=\dfrac {37}{1000}+\dfrac {37}{\left( 1000\right) ^{2}}+\ldots \dfrac {a_{1}}{1-r}=\dfrac {\dfrac {32}{1000}}{1-\dfrac {1}{1000}}=\dfrac {37}{999}$
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