Answer
$=\dfrac {37}{999}$
Work Step by Step
$0.\overline {037}=0.037037...=\dfrac {37}{1000}+\dfrac {37}{\left( 1000\right) ^{2}}+\ldots \dfrac {a_{1}}{1-r}=\dfrac {\dfrac {32}{1000}}{1-\dfrac {1}{1000}}=\dfrac {37}{999}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 8 - Sequences and Infinite Series - 8.3 Infinite Series - 8.3 Exercises - Page 623: 47
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