Answer
$10$
Work Step by Step
$\sum ^{\infty }_{k=0}\left( 0.9\right) ^{k}=\dfrac {a_{1}}{1-r};a_{1}=\left( 0.9\right) ^{0}=1;r=0.9\Rightarrow S_{\infty }=\dfrac {a_{1}}{1-r}=\dfrac {1}{1-0.9}=10$
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