Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 7

Answer

$\ln$ |x| +C

Work Step by Step

Derivative of $\ln$ |x| is $\frac{1}{x}$. So, the antiderivatives of $\frac{1}{x}$, i.e., $\int \frac{1}{x}dx= \ln |x| +C$ where C is arbitrary constant.
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