Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 16

Answer

$Q(s)= -cot$ $s$ $+ c$

Work Step by Step

$Q(s)=csc^{2}s$ $\int Q(s)ds = \int csc^{2}s$ $Q(s)= -cot$ $s$ $+ c$
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