Answer
$H(z) = z^{-6}$
Work Step by Step
$H(z)=-6z^{-7}$
$\int H(z)dz = \int -6z^{-7}$
$H(z) = \frac{-6z^{-7+1}}{-7+1}$
$H(z) = \frac{-6z^{-6}}{-6}$
$H(z) = z^{-6}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 18
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