#### Answer

$F(x)=-\frac{1}{2}cos 2x +c$

#### Work Step by Step

$f(x)=sin2x$
$\int f(x)dx = \int sin 2x$
$F(x)= \frac{1}{2}\int(sin2x)$
$F(x)=-\frac{1}{2}cos 2x +c$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$F(x)=-\frac{1}{2}cos 2x +c$

$f(x)=sin2x$
$\int f(x)dx = \int sin 2x$
$F(x)= \frac{1}{2}\int(sin2x)$
$F(x)=-\frac{1}{2}cos 2x +c$

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