Answer
$G(x)$=$-sin$ $4x+c$
Work Step by Step
$g(x)=-4$ $cos$ $4x$
$\int g(x)dx = -4\int cos$ $4x$
$G(x)= -\frac{4}{4}(sin4x)+c$
$G(x)$=$-sin$ $4x+c$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 327: 14
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