Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises: 14

Answer

$G(x)$=$-sin$ $4x+c$

Work Step by Step

$g(x)=-4$ $cos$ $4x$ $\int g(x)dx = -4\int cos$ $4x$ $G(x)= -\frac{4}{4}(sin4x)+c$ $G(x)$=$-sin$ $4x+c$
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