Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises: 15

Answer

$P(x) = 3$ $tan x +c$

Work Step by Step

$p(x)=3sec^{2}x$ $\int p(x)dx = \int 3sec^{2}x$ $P(x)= 3\int sec^2x$ $P(x) = 3$ $tan x +c$
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