Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.7 The Chain Rule - 3.7 Exercises - Page 191: 5


For the function $(x^2+10)^{-5}$: Inner Function: $x^2+10$ Outer Function: $u^{-5}$

Work Step by Step

With $y=f(u)$ and $u=g(x)$ to represent $f(g(x))$, we can set $y=u^{-5}$ and $u=x^2+10$ to get $(x^2+10)^{-5}$
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