Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.7 The Chain Rule - 3.7 Exercises: 19

Answer

$y '= 10 (3x^2+7x)^9\times (6x + 7)$

Work Step by Step

$y =(3x^2+7x)^{10}$ $y ' =((3x^2+7x)^{10})' $ The inner function sis $g(x) = 3x^2+7x$ and the outer function is $f(u) = u^{10}$ $f'(u) = 10u^9$ $((3x^2+7x)^{10})' = 10 (g(x))^9\times g'(x)$ $= 10 (3x^2+7x)^9\times (6x + 7)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.