$y' = sec^2(e^x)\times e^x$
Work Step by Step
$y = tan(e^x)$ $y' = (tan(e^x))'$ The inner function is $g(x) = e^x$ and the outer function is $f(u) = tan(u)$ $f'(u) = sec^2(u)$ $y' = (tan(e^x))' = sec^2(g(x)) g'(x)= sec^2(e^x)\times e^x$
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