## Calculus: Early Transcendentals (2nd Edition)

Where $y=f(x)$ and $u=g(x)$, the two ways to write the derivative of $y=f(g(x))$ is: 1. $\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}$ 2. $\frac{d}{dx}[f(g(x))] = f'(g(x)) \times g'(x)$
According to Theorem 3.14, where $y=f(x)$ and $u=g(x)$, the two ways to write the derivative of $y=f(g(x))$ is: 1. $\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}$ 2. $\frac{d}{dx}[f(g(x))] = f'(g(x)) \times g'(x)$