Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.6 Surface Integrals - 14.6 Exercises - Page 1123: 9

Answer

$(-Z_x, -Z_y, 1)$

Work Step by Step

Let $Z$ denotes the orientation of a surface of a sphere and is given as: $Z=g(x,y)$ Here, $g(x, y)$ defines the continuous and differentiable function. Next, the normal vector for the given sphere can be expressed as: $(-Z_x, -Z_y, 1)$ in the upward direction.
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