Answer
$x =v \cos u; y=v \sin u$ and $z=v$
Work Step by Step
We are given the equation of a cone as: $z^2=x^2+y^2 $
and $2 \lt z \lt 8$
The parametric description of a sphere with radius $a$ can be expressed as:
$x =v \cos \theta; y=v \sin \theta$ and $z=v$
Suppose that $u=\theta$
Thus, the parametric form of a sphere can be expressed as:
$x =v \cos u; y=v \sin u$ and $z=v$ and ; $0 \lt u \lt 2 \pi$
