Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 14 - Vector Calculus - 14.6 Surface Integrals - 14.6 Exercises - Page 1123: 18

Answer

$ z= 2-y$ for $0 \leq x \leq 2; 0 \leq y \leq 4 $

Work Step by Step

We are given the parametric equation of the plane as: $r (u, v)=\lt u, u+v, 2-u-v \gt$ and $0 \leq u \leq 2; 0 \leq v \leq 2 $ Suppose that $u=x; y=u+v$ Thus, the equation of a plane can be expressed as: $ z= 2-y$ for $0 \leq x \leq 2; 0 \leq y \leq 4 $
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