Answer
$y= \frac{-1}{x^{3} + C}$
Work Step by Step
$\frac{dy}{dx} = 3x^{2}y^{2} $
$\frac{dy}{y^2} = 3x^{2}dx $
$\int {y^{-2}{dy}} = \int 3x^{2}dx $
$\frac{-1}{y} = x^{3} + C$
$y= \frac{-1}{x^{3} + C}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 9 - Differential Equations - 9.3 Separable Equations - 9.3 Exercises - Page 645: 1
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