Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.4 Indefinite Integrals and the Net Change Theorem - 4.4 Exercises - Page 336: 6



Work Step by Step

$$A=\int{\sqrt[4] {x^5}}dx$$ $$A=\int{x^{5/4}}dx$$ According to Table 1, we know that $\int{x^n}dx=\frac{x^{n+1}}{n+1}$. Therefore, $$A=\frac{x^{9/4}}{\frac{9}{4}}+C=\frac{4x^{9/4}}{9}+C$$ $$A=\frac{4\sqrt[4]{x^9}}{9}+C$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.