## Calculus 8th Edition

Verify $\int\tan^2{x}dx=\tan{x}-x+C$ We need to take the derivative of the right side of our equation and verify that it equals the expression inside of our integral. \begin{equation*} \frac{d}{dx}\left(\tan{x}-x+C\right)=\frac{d}{dx}\left(\tan{x}\right)-\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(C\right) \end{equation*} \begin{equation*} =\left(\sec^2{x}\right)-\left(1\right)+\left(0\right) \end{equation*} \begin{equation*} =\tan^2{x} \end{equation*} as desired.
Verify $\int\tan^2{x}dx=\tan{x}-x+C$ We need to take the derivative of the right side of our equation and verify that it equals the expression inside of our integral. \begin{equation*} \frac{d}{dx}\left(\tan{x}-x+C\right)=\frac{d}{dx}\left(\tan{x}\right)-\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(C\right) \end{equation*} \begin{equation*} =\left(\sec^2{x}\right)-\left(1\right)+\left(0\right) \end{equation*} \begin{equation*} =\tan^2{x} \end{equation*} as desired.