## Calculus 8th Edition

$\frac{u^3}{3} + u - \frac{1}{u} + C$
We can evaluate each term's integral separately and take the sum of the results, which would be $\frac{u^3}{3} + u - \frac{1}{u} + C$ It is important to note for the third term that there is a negative present from the exponent, as $\frac{1}{u^2} = u^{-2}$ Lastly, we need to include the constant $C$ since the indefinite integral has an unknown constant that must be accounted for.