Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.4 Indefinite Integrals and the Net Change Theorem - 4.4 Exercises - Page 336: 5


$\frac{x^{2.3}}{2.3} +2x^{3.5}+C$

Work Step by Step

We begin by recognizing that the two terms containing x are being summed, so we can deal with them individually. We use the reverse of the power rule to integrate each term. So: $\int(x^{1.3}+7x^{2.5})dx$ Becomes: $\frac{x^{1.3+1}}{1.3+1} +\frac{7x^{2.5+1}}{2.5+1}+C$ We can then simplify to get our final answer: $\frac{x^{2.3}}{2.3} +2x^{3.5}+C$
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