Answer
$-\frac{10}{3}$
Work Step by Step
We evaluate the integrand $\int x^2 -3 dx$, which equals $\frac {x^3}{3} -3x\Big|_-2^3$
Substituting 3 and -2 into $x$, we get $(\frac {3^3}{3} - 3(3)) - (\frac {2^3}{3} - 3(2)) $ $ = (0) - (\frac{8}{3} - 6) = -\frac{10}{3}$