## Calculus 8th Edition

Maclaurin's series is: $\Sigma_{n=0}^{\infty}(n+1)x^{n}$ and $R=1$
$\lim\limits_{n \to \infty}|\frac{a_{n+1}}{a_{n}}|=\lim\limits_{n \to \infty}|\frac{{(n+2)}x^{n+1}}{(n+1)x^{n}}|$ $=\lim\limits_{n \to\infty}|(\frac{n+2}{n+1}).x|$ $=|x|\lt 1$ Maclaurin's series is: $\Sigma_{n=0}^{\infty}(n+1)x^{n}$ and $R=1$