Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.2 Calculus with Parametric Curves - 10.2 Exercises - Page 696: 57

Answer

$S\approx 4.7394$

Work Step by Step

$x$ = $t\sin t$ $y$ = $t\cos t$ $\frac{dx}{dt}$ = $t\cos t+\sin t$ $\frac{dy}{dt}$ = $-t\sin t+\cos t$ $\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2$ = $(t\cos t+\sin t)^2+(-t\sin t+\cos t)^2$ $=t^2\cos^2t+2t\sin t\cos t+\sin^2t+t^2\sin^2t-2t\sin t\cos t+\cos^2t$ $=t^2+1$ $S$ = $\int2{\pi}yds$ $S$ = $\int_0^{\frac{\pi}{2}}2{\pi}t\cos t\sqrt {t^2+1}dt$ $\approx$ $4.7394$
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