# Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 39

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#### Work Step by Step

See The Squeeze Theorem, p.69: If $f(x) \leq g(x) \leq h(x)$, and $\displaystyle \lim_{x\rightarrow a}f(x)= \displaystyle \lim_{x\rightarrow a}h(x)=L,$ then $\displaystyle \lim_{x\rightarrow a}g(x)=L.$ ------ $\displaystyle \lim_{x\rightarrow 1}(2\mathrm{x}-1)=1$ $\displaystyle \lim_{x\rightarrow 1}(x^{2})=1$ so, by the squeeze theorem, $\displaystyle \lim_{x\rightarrow 1}f(x)=1$

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