Answer
$-1$
Work Step by Step
$\lim _{x\rightarrow 1}\left( \dfrac {1}{x-1}+\dfrac {1}{x^{2}-3x+2}\right) =\dfrac {1}{x-1}+\dfrac {1}{\left( x-2\right) \left( x-1\right) }=\dfrac {x-2+1}{\left( x-2\right) \left( x-1\right) }=\dfrac {1}{x-2}=-1$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 38
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