Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 26



Work Step by Step

$\lim\limits_{x \to 3}\dfrac{x^2-9}{x^2+2x-3}$ Factor. $\lim\limits_{x \to 3}\dfrac{(x+3)(x-3)}{(x+3)(x-1)}$ The $(x+3)$ cancels out. $\lim\limits_{x \to 3}\dfrac{x-3}{x-1}$ Plug in 3. $\lim\limits_{x \to 3}\dfrac{3-3}{3-1}=\dfrac{0}{2}=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.