Answer
0
Work Step by Step
$\lim\limits_{x \to 3}\dfrac{x^2-9}{x^2+2x-3}$
Factor.
$\lim\limits_{x \to 3}\dfrac{(x+3)(x-3)}{(x+3)(x-1)}$
The $(x+3)$ cancels out.
$\lim\limits_{x \to 3}\dfrac{x-3}{x-1}$
Plug in 3.
$\lim\limits_{x \to 3}\dfrac{3-3}{3-1}=\dfrac{0}{2}=0$
