## Calculus 8th Edition

$-\infty$
$\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}$ Graph the function (image attached below). As $x$ approaches 1 from the right hand side, y goes to $-\infty$. Therefore, $\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}=-\infty$