Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 28

Answer

$-\infty$

Work Step by Step

$\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}$ Graph the function (image attached below). As $x$ approaches 1 from the right hand side, y goes to $-\infty$. Therefore, $\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}=-\infty$
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