Answer
$-\infty$
Work Step by Step
$\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}$
Graph the function (image attached below).
As $x$ approaches 1 from the right hand side, y goes to $-\infty$.
Therefore,
$\lim\limits_{x \to 1^+}\dfrac{x^2-9}{x^2+2x-3}=-\infty$
