Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 29

Answer

3

Work Step by Step

$\lim\limits_{h \to 0}\dfrac{(h-1)^3+1}{h}$ Expand: $\lim\limits_{h \to 0}\dfrac{h^3-3h^2+3h-1+1}{h}$ $\lim\limits_{h \to 0}\dfrac{h^3-3h^2+3h}{h}$ $\lim\limits_{h \to 0}h^2-3h+3$ Plug in 0: $0^2-3(0)+3=3$ $\lim\limits_{h \to 0}\dfrac{(h-1)^3+1}{h}=3$
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