## Calculus 8th Edition

$\lim\limits_{h \to 0}\dfrac{(h-1)^3+1}{h}$ Expand: $\lim\limits_{h \to 0}\dfrac{h^3-3h^2+3h-1+1}{h}$ $\lim\limits_{h \to 0}\dfrac{h^3-3h^2+3h}{h}$ $\lim\limits_{h \to 0}h^2-3h+3$ Plug in 0: $0^2-3(0)+3=3$ $\lim\limits_{h \to 0}\dfrac{(h-1)^3+1}{h}=3$