Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises: 35

Answer

$-\dfrac {1}{8}$

Work Step by Step

$\lim _{s\rightarrow 16}\dfrac {4-\sqrt {s}}{s-16}=\dfrac {-\left( \sqrt {s}-4\right) }{\left( \sqrt {s}-4\right) \left( \sqrt {s}+4\right) }=-\dfrac {1}{\sqrt {s}+4}=-\dfrac {1}{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.