Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 374: 4



Work Step by Step

Let $\sec^{-1}\frac{2}{\sqrt 3}=x $, then we have $$\sec x =\frac{2}{\sqrt 3}\Longrightarrow x=\frac{\pi}{6}.$$
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