Answer
$$\frac{1}{20}.$$
Work Step by Step
Assume that $\csc\theta =\frac{20}{1}$, then by solving the triangle, we have:
$$\sin\theta=\frac{1}{20}.$$
Now, since $\theta =\csc^{-1}20 $, we have
$$\sin(\csc^{-1}20 )=\sin\theta=\frac{1}{20}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 374: 28
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