Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 374: 30



Work Step by Step

Since $ y=\tan^{-1}x $, then $$ y'= \frac{1}{1+x^2}.$$ Now, we have $$ y'(1/2)= \frac{1}{1+(1/2)^2}=\frac{1}{(5/4)}=\frac{4}{5}.$$
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