Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 374: 23

Answer

$$\frac{4}{3} $$

Work Step by Step

Assume that $\sin\theta =\frac{8}{10}$, then by solving the triangle, we have: $$\tan \theta=\frac{8}{6}=\frac{4}{3}.$$ Now, since $\theta =\sin^{-1}\frac{8}{10} $, we have $$\tan(\sin^{-1}\frac{8}{10} )=\tan\theta=\frac{4}{3} .$$
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