Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 23



Work Step by Step

$\ln{x^4}-\ln{x^2}=2$ Since $\log{a}-\log{b}=\log{\frac{a}{b}}$, $\ln\frac{x^4}{x^2}=2$ Thus, $\ln{x^2}=2$ Raising $e$ to the power of both sides: $x^2=e^2$ Solving for $x$: $x=±e$
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