Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 20



Work Step by Step

$6e^{-4t}=2$ Dividing both sides by 6: $e^{-4t}=\frac{2}{6}=\frac{1}{3}$ Taking the natural log of both sides: $-4t=\ln{\frac{1}{3}}=\ln({3^{-1})}=-\ln3$ Solving for $t$: $t=\frac{1}{4}\ln3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.