Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 10

Answer

$$1$$

Work Step by Step

$\log_{25} {30} + \log_{25}{\frac{5}{6}}$ $=\log_{25} ({30\times\frac{5}{6}})$ {Since $\log{a}+\log{b}=\log{ab}$} $=\log_{25} {\frac{150}{6}} = \log_{25}{25} = 1$
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