## Calculus (3rd Edition)

a) $$\ln1600$$ b) $$\ln({9x^{7/2}})$$
a) $2\ln5+3\ln4$ $=\ln{5^2}+\ln{4^3}$ $=\ln25+\ln64$ $=\ln({25\times64})$ $= \ln1600$ b) $5\ln{(x^{1/2})}+\ln{9x}$ $=\ln(x^{5/2})+\ln{9x}$ $=\ln{(x^{5/2} \times 9x)}$ $=\ln({9x^{7/2}})$