Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 11

Answer

$$1$$

Work Step by Step

$\log_4{48}-\log_4{12}$ $=\log_4{\frac{48}{12}}$ {Since $\log{a}-\log{b}=\log{\frac{a}{b}}$} $=\log_4{4}=1$
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