Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 43

Answer

$$\infty$$

Work Step by Step

We evaluate the limit: \begin{align*} \lim _{x \rightarrow 1+}\left(\frac{1}{\sqrt{x-1}}-\frac{1}{\sqrt{x^{2}-1}}\right)&=\lim _{x \rightarrow 1+} \frac{\sqrt{x+1}-1}{\sqrt{x^{2}-1}}\\ &=\infty \end{align*}
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