Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 33



Work Step by Step

We evaluate the limit: \begin{aligned} \lim _{x \rightarrow 0}\left(\frac{1}{3 x}-\frac{1}{x(x+3)}\right)&=\lim _{x \rightarrow 0} \frac{x+3-3}{3 x(x+3)} \\ &=\lim _{x \rightarrow 0} \frac{x}{3 x(x+3)}\\ &=\lim _{x \rightarrow 0} \frac{ 1}{3 (x+3)}\\ &=\frac{1}{9} \end{aligned}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.