Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 44

Answer

$$-\sqrt{\pi}$$

Work Step by Step

We have $$ \lim _{t \rightarrow \frac{\pi}{2}} \sqrt{2t}(\cos t-1)= \sqrt{\pi}(\cos \frac{\pi}{2}-1)=\sqrt{\pi}(0-1)=-\sqrt{\pi}. $$
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