Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 41


$ \infty $

Work Step by Step

We have $$ \lim _{x \rightarrow 2^-} \frac{x-3}{x-2 }= \frac{2-3}{0^- }=\frac{-1}{0^-}=\infty. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.