Answer
$ \infty $
Work Step by Step
We have
$$
\lim _{x \rightarrow 2^-} \frac{x-3}{x-2 }= \frac{2-3}{0^- }=\frac{-1}{0^-}=\infty.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - Chapter Review Exercises - Page 94: 41
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