Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 14



Work Step by Step

\begin{align*} \lim _{x \rightarrow -1} \frac{3x^2+4x+1}{x+1} &= \lim _{x \rightarrow -1} \frac{(x+1)(3x+1)}{x+1} \\ &=\lim _{x \rightarrow -1} (3x+1) \\ &=-3+1\\ &=-2. \end{align*}
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