Answer
$-2$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow -1} \frac{3x^2+4x+1}{x+1} &= \lim _{x \rightarrow -1} \frac{(x+1)(3x+1)}{x+1} \\
&=\lim _{x \rightarrow -1} (3x+1) \\
&=-3+1\\
&=-2.
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - Chapter Review Exercises - Page 94: 14
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