Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 15


$\frac{ 1}{6}$

Work Step by Step

\begin{align*} \lim _{t \rightarrow 9} \frac{\sqrt t -3}{t-9} &= \lim _{t \rightarrow 9} \frac{\sqrt t -3}{(\sqrt t -3)(\sqrt t +3)}\\ &=\lim _{t \rightarrow 9} \frac{ 1}{(\sqrt t +3)}\\ &=\frac{ 1}{(\sqrt 9 +3)}\\ &=\frac{ 1}{6}. \end{align*}
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