Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 650: 50

Answer

$$\mathbf{v}= \langle 2,-1\rangle $$

Work Step by Step

$$ 3 \mathbf{v}+\langle 5,20\rangle=\langle 11,17\rangle \Longrightarrow 3 \mathbf{v}=\langle 11- 5,17-20\rangle\\ \Longrightarrow \mathbf{v}=\frac{1}{3}\langle 6,-3\rangle=\langle 2,-1\rangle $$
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