## Calculus (3rd Edition)

The components of $v$ are given by $$v=\overrightarrow{P Q}=Q-P=(1,-2)-(-2,5)=(3,-7).$$ The vector in (b) is given by $(0,0)-(3,-7)=(-3,7)$ so it is equivalent to $v$ (a scalar multiple of $v$). The vector in (c) is given by $(-1,2)-(2,-5)=(-3,7)$ so (c) is equivalent to $v$ (a scalar multiple of $v$). The other choices, (a) and (d) are not equivalent to $v$ (they are not scalar multiples of $v$).