Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 650: 49


$\lambda=\pm\frac{1}{\sqrt{ 13}}$.

Work Step by Step

The length is given by $$|\lambda|\sqrt{4+9}=1\Longrightarrow 13\lambda^2=1. $$ Hence, $\lambda=\pm\frac{1}{\sqrt{ 13}}$.
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